Container D and Container E were filled completely with chicken powder. The total mass of ¹₃ of the chicken powder in Container E and ¹₇ of the chicken powder in Container D was 490 g. If ²₇ of the chicken powder in Container D was poured out, the total mass of the chicken powder in both containers became 1.79 kg. How much chicken powder was in

1. Container D in grams?
2. Container E in grams?

(a)
Let the mass of the chicken powder in Container E be E.
Let the mass of the chicken powder in Container D be D.

¹₃ E + ¹₇ D = 490 --- (1)

Fraction of the chicken powder left in Container D after ²₇ of it was poured out
= 1 - ²₇
= ⁵₇

1 kg = 1000 g
1.79 kg = 1790 g

1 E + ⁵₇ D = 1790
1 E = 1790 - ⁵₇ D --- (2)

Make E the same.

(1)_x3
³₃ E + ³₇ D = 1470
1 E + ³₇ D = 1470
1 E = 1470 - ³₇ D --- (3)

(3) = (2) 
1470 - ³₇ D = 1790 - ⁵₇ X
⁵₇ D - ³₇ D = 1790 - 1470
²₇ D = 320
¹₇ D = 320 ÷ 2 = 160

⁷₇ D = 7 x 160 = 1120

1 D = 1120

Mass of Container D = 1120 g

(b)
From (1)
¹₃ E + 160 = 490
¹₃ E = 490 - 160 = 330

³₃ E = 3 x 330 = 990

1 E = 990

Mass of Container E = 990 g

Answer(s): (a) 1120 g; (b) 990 g