Container J and Container K were filled completely with chilli powder. The total mass of
13 of the chilli powder in Container K and
111 of the chilli powder in Container J was 620 g. If
411 of the chilli powder in Container J was poured out, the total mass of the chilli powder in both containers became 2.66 kg. How much chilli powder was in
- Container J in grams?
- Container K in grams?
(a)
Let the mass of the chilli powder in Container K be K.
Let the mass of the chilli powder in Container J be J.
13 K +
111 J = 620 --- (1)
Fraction of the chilli powder left in Container J after
411 of it was poured out
= 1 -
411 =
711 1 kg = 1000 g
2.66 kg = 2660 g
1 K +
711 J = 2660
1 K = 2660 -
711 J --- (2)
Make K the same.
(1)
x3 33 K +
311 J = 1860
1 K +
311 J = 1860
1 K = 1860 -
311 J --- (3)
(3) = (2)
1860 -
311 J = 2660 -
711 X
711 J -
311 J = 2660 - 1860
411 J = 800
111 J = 800 ÷ 4 = 200
1111 J = 11 x 200 = 2200
1 J = 2200
Mass of Container J = 2200 g
(b)
From (1)
13 K + 200 = 620
13 K = 620 - 200 = 420
33 K = 3 x 420 = 1260
1 K = 1260
Mass of Container K = 1260 g
Answer(s): (a) 2200 g; (b) 1260 g