Container S and Container T were filled completely with bread flour. The total mass of ¹₇ of the bread flour in Container T and ¹₁₃ of the bread flour in Container S was 480 g. If ²₁₃ of the bread flour in Container S was poured out, the total mass of the bread flour in both containers became 4 kg. How much bread flour was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the bread flour in Container T be T.
Let the mass of the bread flour in Container S be S.

¹₇ T + ¹₁₃ S = 480 --- (1)

Fraction of the bread flour left in Container S after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
4 kg = 4000 g

1 T + ¹¹₁₃ S = 4000
1 T = 4000 - ¹¹₁₃ S --- (2)

Make T the same.

(1)_x7
⁷₇ T + ⁷₁₃ S = 3360
1 T + ⁷₁₃ S = 3360
1 T = 3360 - ⁷₁₃ S --- (3)

(3) = (2) 
3360 - ⁷₁₃ S = 4000 - ¹¹₁₃ X
¹¹₁₃ S - ⁷₁₃ S = 4000 - 3360
⁴₁₃ S = 640
¹₁₃ S = 640 ÷ 4 = 160

¹³₁₃ S = 13 x 160 = 2080

1 S = 2080

Mass of Container S = 2080 g

(b)
From (1)
¹₇ T + 160 = 480
¹₇ T = 480 - 160 = 320

⁷₇ T = 7 x 320 = 2240

1 T = 2240

Mass of Container T = 2240 g

Answer(s): (a) 2080 g; (b) 2240 g