Container P and Container Q were filled completely with pepper. The total mass of ¹₄ of the pepper in Container Q and ¹₁₁ of the pepper in Container P was 520 g. If ²₁₁ of the pepper in Container P was poured out, the total mass of the pepper in both containers became 2.63 kg. How much pepper was in

1. Container P in grams?
2. Container Q in grams?

(a)
Let the mass of the pepper in Container Q be Q.
Let the mass of the pepper in Container P be P.

¹₄ Q + ¹₁₁ P = 520 --- (1)

Fraction of the pepper left in Container P after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
2.63 kg = 2630 g

1 Q + ⁹₁₁ P = 2630
1 Q = 2630 - ⁹₁₁ P --- (2)

Make Q the same.

(1)_x4
⁴₄ Q + ⁴₁₁ P = 2080
1 Q + ⁴₁₁ P = 2080
1 Q = 2080 - ⁴₁₁ P --- (3)

(3) = (2) 
2080 - ⁴₁₁ P = 2630 - ⁹₁₁ X
⁹₁₁ P - ⁴₁₁ P = 2630 - 2080
⁵₁₁ P = 550
¹₁₁ P = 550 ÷ 5 = 110

¹¹₁₁ P = 11 x 110 = 1210

1 P = 1210

Mass of Container P = 1210 g

(b)
From (1)
¹₄ Q + 110 = 520
¹₄ Q = 520 - 110 = 410

⁴₄ Q = 4 x 410 = 1640

1 Q = 1640

Mass of Container Q = 1640 g

Answer(s): (a) 1210 g; (b) 1640 g