Container Y and Container Z were filled completely with pepper. The total mass of ¹₇ of the pepper in Container Z and ¹₁₃ of the pepper in Container Y was 450 g. If ³₁₃ of the pepper in Container Y was poured out, the total mass of the pepper in both containers became 3.48 kg. How much pepper was in

1. Container Y in grams?
2. Container Z in grams?

(a)
Let the mass of the pepper in Container Z be Z.
Let the mass of the pepper in Container Y be Y.

¹₇ Z + ¹₁₃ Y = 450 --- (1)

Fraction of the pepper left in Container Y after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.48 kg = 3480 g

1 Z + ¹⁰₁₃ Y = 3480
1 Z = 3480 - ¹⁰₁₃ Y --- (2)

Make Z the same.

(1)_x7
⁷₇ Z + ⁷₁₃ Y = 3150
1 Z + ⁷₁₃ Y = 3150
1 Z = 3150 - ⁷₁₃ Y --- (3)

(3) = (2) 
3150 - ⁷₁₃ Y = 3480 - ¹⁰₁₃ X
¹⁰₁₃ Y - ⁷₁₃ Y = 3480 - 3150
³₁₃ Y = 330
¹₁₃ Y = 330 ÷ 3 = 110

¹³₁₃ Y = 13 x 110 = 1430

1 Y = 1430

Mass of Container Y = 1430 g

(b)
From (1)
¹₇ Z + 110 = 450
¹₇ Z = 450 - 110 = 340

⁷₇ Z = 7 x 340 = 2380

1 Z = 2380

Mass of Container Z = 2380 g

Answer(s): (a) 1430 g; (b) 2380 g