Container E and Container F were filled completely with chilli powder. The total mass of
15 of the chilli powder in Container F and
111 of the chilli powder in Container E was 540 g. If
311 of the chilli powder in Container E was poured out, the total mass of the chilli powder in both containers became 3.12 kg. How much chilli powder was in
- Container E in grams?
- Container F in grams?
(a)
Let the mass of the chilli powder in Container F be F.
Let the mass of the chilli powder in Container E be E.
15 F +
111 E = 540 --- (1)
Fraction of the chilli powder left in Container E after
311 of it was poured out
= 1 -
311 =
811 1 kg = 1000 g
3.12 kg = 3120 g
1 F +
811 E = 3120
1 F = 3120 -
811 E --- (2)
Make F the same.
(1)
x5 55 F +
511 E = 2700
1 F +
511 E = 2700
1 F = 2700 -
511 E --- (3)
(3) = (2)
2700 -
511 E = 3120 -
811 X
811 E -
511 E = 3120 - 2700
311 E = 420
111 E = 420 ÷ 3 = 140
1111 E = 11 x 140 = 1540
1 E = 1540
Mass of Container E = 1540 g
(b)
From (1)
15 F + 140 = 540
15 F = 540 - 140 = 400
55 F = 5 x 400 = 2000
1 F = 2000
Mass of Container F = 2000 g
Answer(s): (a) 1540 g; (b) 2000 g