Container H and Container J were filled completely with rice flour. The total mass of ¹₇ of the rice flour in Container J and ¹₁₃ of the rice flour in Container H was 430 g. If ²₁₃ of the rice flour in Container H was poured out, the total mass of the rice flour in both containers became 3.41 kg. How much rice flour was in

1. Container H in grams?
2. Container J in grams?

(a)
Let the mass of the rice flour in Container J be J.
Let the mass of the rice flour in Container H be H.

¹₇ J + ¹₁₃ H = 430 --- (1)

Fraction of the rice flour left in Container H after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
3.41 kg = 3410 g

1 J + ¹¹₁₃ H = 3410
1 J = 3410 - ¹¹₁₃ H --- (2)

Make J the same.

(1)_x7
⁷₇ J + ⁷₁₃ H = 3010
1 J + ⁷₁₃ H = 3010
1 J = 3010 - ⁷₁₃ H --- (3)

(3) = (2) 
3010 - ⁷₁₃ H = 3410 - ¹¹₁₃ X
¹¹₁₃ H - ⁷₁₃ H = 3410 - 3010
⁴₁₃ H = 400
¹₁₃ H = 400 ÷ 4 = 100

¹³₁₃ H = 13 x 100 = 1300

1 H = 1300

Mass of Container H = 1300 g

(b)
From (1)
¹₇ J + 100 = 430
¹₇ J = 430 - 100 = 330

⁷₇ J = 7 x 330 = 2310

1 J = 2310

Mass of Container J = 2310 g

Answer(s): (a) 1300 g; (b) 2310 g