Container K and Container L were filled completely with curry powder. The total mass of ¹₅ of the curry powder in Container L and ¹₁₁ of the curry powder in Container K was 510 g. If ³₁₁ of the curry powder in Container K was poured out, the total mass of the curry powder in both containers became 3.09 kg. How much curry powder was in

1. Container K in grams?
2. Container L in grams?

(a)
Let the mass of the curry powder in Container L be L.
Let the mass of the curry powder in Container K be K.

¹₅ L + ¹₁₁ K = 510 --- (1)

Fraction of the curry powder left in Container K after ³₁₁ of it was poured out
= 1 - ³₁₁
= ⁸₁₁

1 kg = 1000 g
3.09 kg = 3090 g

1 L + ⁸₁₁ K = 3090
1 L = 3090 - ⁸₁₁ K --- (2)

Make L the same.

(1)_x5
⁵₅ L + ⁵₁₁ K = 2550
1 L + ⁵₁₁ K = 2550
1 L = 2550 - ⁵₁₁ K --- (3)

(3) = (2) 
2550 - ⁵₁₁ K = 3090 - ⁸₁₁ X
⁸₁₁ K - ⁵₁₁ K = 3090 - 2550
³₁₁ K = 540
¹₁₁ K = 540 ÷ 3 = 180

¹¹₁₁ K = 11 x 180 = 1980

1 K = 1980

Mass of Container K = 1980 g

(b)
From (1)
¹₅ L + 180 = 510
¹₅ L = 510 - 180 = 330

⁵₅ L = 5 x 330 = 1650

1 L = 1650

Mass of Container L = 1650 g

Answer(s): (a) 1980 g; (b) 1650 g