Container S and Container T were filled completely with bread flour. The total mass of
16 of the bread flour in Container T and
113 of the bread flour in Container S was 570 g. If
413 of the bread flour in Container S was poured out, the total mass of the bread flour in both containers became 3.81 kg. How much bread flour was in
- Container S in grams?
- Container T in grams?
(a)
Let the mass of the bread flour in Container T be T.
Let the mass of the bread flour in Container S be S.
16 T +
113 S = 570 --- (1)
Fraction of the bread flour left in Container S after
413 of it was poured out
= 1 -
413 =
913 1 kg = 1000 g
3.81 kg = 3810 g
1 T +
913 S = 3810
1 T = 3810 -
913 S --- (2)
Make T the same.
(1)
x6 66 T +
613 S = 3420
1 T +
613 S = 3420
1 T = 3420 -
613 S --- (3)
(3) = (2)
3420 -
613 S = 3810 -
913 X
913 S -
613 S = 3810 - 3420
313 S = 390
113 S = 390 ÷ 3 = 130
1313 S = 13 x 130 = 1690
1 S = 1690
Mass of Container S = 1690 g
(b)
From (1)
16 T + 130 = 570
16 T = 570 - 130 = 440
66 T = 6 x 440 = 2640
1 T = 2640
Mass of Container T = 2640 g
Answer(s): (a) 1690 g; (b) 2640 g