Container S and Container T were filled completely with curry powder. The total mass of ¹₄ of the curry powder in Container T and ¹₁₃ of the curry powder in Container S was 600 g. If ³₁₃ of the curry powder in Container S was poured out, the total mass of the curry powder in both containers became 3.3 kg. How much curry powder was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the curry powder in Container T be T.
Let the mass of the curry powder in Container S be S.

¹₄ T + ¹₁₃ S = 600 --- (1)

Fraction of the curry powder left in Container S after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.3 kg = 3300 g

1 T + ¹⁰₁₃ S = 3300
1 T = 3300 - ¹⁰₁₃ S --- (2)

Make T the same.

(1)_x4
⁴₄ T + ⁴₁₃ S = 2400
1 T + ⁴₁₃ S = 2400
1 T = 2400 - ⁴₁₃ S --- (3)

(3) = (2) 
2400 - ⁴₁₃ S = 3300 - ¹⁰₁₃ X
¹⁰₁₃ S - ⁴₁₃ S = 3300 - 2400
⁶₁₃ S = 900
¹₁₃ S = 900 ÷ 6 = 150

¹³₁₃ S = 13 x 150 = 1950

1 S = 1950

Mass of Container S = 1950 g

(b)
From (1)
¹₄ T + 150 = 600
¹₄ T = 600 - 150 = 450

⁴₄ T = 4 x 450 = 1800

1 T = 1800

Mass of Container T = 1800 g

Answer(s): (a) 1950 g; (b) 1800 g