Container G and Container H were filled completely with chicken powder. The total mass of
14 of the chicken powder in Container H and
111 of the chicken powder in Container G was 400 g. If
211 of the chicken powder in Container G was poured out, the total mass of the chicken powder in both containers became 2.1 kg. How much chicken powder was in
- Container G in grams?
- Container H in grams?
(a)
Let the mass of the chicken powder in Container H be H.
Let the mass of the chicken powder in Container G be G.
14 H +
111 G = 400 --- (1)
Fraction of the chicken powder left in Container G after
211 of it was poured out
= 1 -
211 =
911 1 kg = 1000 g
2.1 kg = 2100 g
1 H +
911 G = 2100
1 H = 2100 -
911 G --- (2)
Make H the same.
(1)
x4 44 H +
411 G = 1600
1 H +
411 G = 1600
1 H = 1600 -
411 G --- (3)
(3) = (2)
1600 -
411 G = 2100 -
911 X
911 G -
411 G = 2100 - 1600
511 G = 500
111 G = 500 ÷ 5 = 100
1111 G = 11 x 100 = 1100
1 G = 1100
Mass of Container G = 1100 g
(b)
From (1)
14 H + 100 = 400
14 H = 400 - 100 = 300
44 H = 4 x 300 = 1200
1 H = 1200
Mass of Container H = 1200 g
Answer(s): (a) 1100 g; (b) 1200 g