Container X and Container Y were filled completely with bread flour. The total mass of
16 of the bread flour in Container Y and
113 of the bread flour in Container X was 430 g. If
213 of the bread flour in Container X was poured out, the total mass of the bread flour in both containers became 3.08 kg. How much bread flour was in
- Container X in grams?
- Container Y in grams?
(a)
Let the mass of the bread flour in Container Y be Y.
Let the mass of the bread flour in Container X be X.
16 Y +
113 X = 430 --- (1)
Fraction of the bread flour left in Container X after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
3.08 kg = 3080 g
1 Y +
1113 X = 3080
1 Y = 3080 -
1113 X --- (2)
Make Y the same.
(1)
x6 66 Y +
613 X = 2580
1 Y +
613 X = 2580
1 Y = 2580 -
613 X --- (3)
(3) = (2)
2580 -
613 X = 3080 -
1113 X
1113 X -
613 X = 3080 - 2580
513 X = 500
113 X = 500 ÷ 5 = 100
1313 X = 13 x 100 = 1300
1 X = 1300
Mass of Container X = 1300 g
(b)
From (1)
16 Y + 100 = 430
16 Y = 430 - 100 = 330
66 Y = 6 x 330 = 1980
1 Y = 1980
Mass of Container Y = 1980 g
Answer(s): (a) 1300 g; (b) 1980 g