Container F and Container G were filled completely with bread flour. The total mass of ¹₅ of the bread flour in Container G and ¹₁₃ of the bread flour in Container F was 600 g. If ²₁₃ of the bread flour in Container F was poured out, the total mass of the bread flour in both containers became 4.08 kg. How much bread flour was in

1. Container F in grams?
2. Container G in grams?

(a)
Let the mass of the bread flour in Container G be G.
Let the mass of the bread flour in Container F be F.

¹₅ G + ¹₁₃ F = 600 --- (1)

Fraction of the bread flour left in Container F after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
4.08 kg = 4080 g

1 G + ¹¹₁₃ F = 4080
1 G = 4080 - ¹¹₁₃ F --- (2)

Make G the same.

(1)_x5
⁵₅ G + ⁵₁₃ F = 3000
1 G + ⁵₁₃ F = 3000
1 G = 3000 - ⁵₁₃ F --- (3)

(3) = (2) 
3000 - ⁵₁₃ F = 4080 - ¹¹₁₃ X
¹¹₁₃ F - ⁵₁₃ F = 4080 - 3000
⁶₁₃ F = 1080
¹₁₃ F = 1080 ÷ 6 = 180

¹³₁₃ F = 13 x 180 = 2340

1 F = 2340

Mass of Container F = 2340 g

(b)
From (1)
¹₅ G + 180 = 600
¹₅ G = 600 - 180 = 420

⁵₅ G = 5 x 420 = 2100

1 G = 2100

Mass of Container G = 2100 g

Answer(s): (a) 2340 g; (b) 2100 g