Container C and Container D were filled completely with pepper. The total mass of ¹₃ of the pepper in Container D and ¹₁₁ of the pepper in Container C was 470 g. If ⁵₁₁ of the pepper in Container C was poured out, the total mass of the pepper in both containers became 1.86 kg. How much pepper was in

1. Container C in grams?
2. Container D in grams?

(a)
Let the mass of the pepper in Container D be D.
Let the mass of the pepper in Container C be C.

¹₃ D + ¹₁₁ C = 470 --- (1)

Fraction of the pepper left in Container C after ⁵₁₁ of it was poured out
= 1 - ⁵₁₁
= ⁶₁₁

1 kg = 1000 g
1.86 kg = 1860 g

1 D + ⁶₁₁ C = 1860
1 D = 1860 - ⁶₁₁ C --- (2)

Make D the same.

(1)_x3
³₃ D + ³₁₁ C = 1410
1 D + ³₁₁ C = 1410
1 D = 1410 - ³₁₁ C --- (3)

(3) = (2) 
1410 - ³₁₁ C = 1860 - ⁶₁₁ X
⁶₁₁ C - ³₁₁ C = 1860 - 1410
³₁₁ C = 450
¹₁₁ C = 450 ÷ 3 = 150

¹¹₁₁ C = 11 x 150 = 1650

1 C = 1650

Mass of Container C = 1650 g

(b)
From (1)
¹₃ D + 150 = 470
¹₃ D = 470 - 150 = 320

³₃ D = 3 x 320 = 960

1 D = 960

Mass of Container D = 960 g

Answer(s): (a) 1650 g; (b) 960 g