Container G and Container H were filled completely with chilli powder. The total mass of
13 of the chilli powder in Container H and
111 of the chilli powder in Container G was 500 g. If
411 of the chilli powder in Container G was poured out, the total mass of the chilli powder in both containers became 2.14 kg. How much chilli powder was in
- Container G in grams?
- Container H in grams?
(a)
Let the mass of the chilli powder in Container H be H.
Let the mass of the chilli powder in Container G be G.
13 H +
111 G = 500 --- (1)
Fraction of the chilli powder left in Container G after
411 of it was poured out
= 1 -
411 =
711 1 kg = 1000 g
2.14 kg = 2140 g
1 H +
711 G = 2140
1 H = 2140 -
711 G --- (2)
Make H the same.
(1)
x3 33 H +
311 G = 1500
1 H +
311 G = 1500
1 H = 1500 -
311 G --- (3)
(3) = (2)
1500 -
311 G = 2140 -
711 X
711 G -
311 G = 2140 - 1500
411 G = 640
111 G = 640 ÷ 4 = 160
1111 G = 11 x 160 = 1760
1 G = 1760
Mass of Container G = 1760 g
(b)
From (1)
13 H + 160 = 500
13 H = 500 - 160 = 340
33 H = 3 x 340 = 1020
1 H = 1020
Mass of Container H = 1020 g
Answer(s): (a) 1760 g; (b) 1020 g