Container L and Container M were filled completely with sugar. The total mass of
13 of the sugar in Container M and
111 of the sugar in Container L was 520 g. If
211 of the sugar in Container L was poured out, the total mass of the sugar in both containers became 2.52 kg. How much sugar was in
- Container L in grams?
- Container M in grams?
(a)
Let the mass of the sugar in Container M be M.
Let the mass of the sugar in Container L be L.
13 M +
111 L = 520 --- (1)
Fraction of the sugar left in Container L after
211 of it was poured out
= 1 -
211 =
911 1 kg = 1000 g
2.52 kg = 2520 g
1 M +
911 L = 2520
1 M = 2520 -
911 L --- (2)
Make M the same.
(1)
x3 33 M +
311 L = 1560
1 M +
311 L = 1560
1 M = 1560 -
311 L --- (3)
(3) = (2)
1560 -
311 L = 2520 -
911 X
911 L -
311 L = 2520 - 1560
611 L = 960
111 L = 960 ÷ 6 = 160
1111 L = 11 x 160 = 1760
1 L = 1760
Mass of Container L = 1760 g
(b)
From (1)
13 M + 160 = 520
13 M = 520 - 160 = 360
33 M = 3 x 360 = 1080
1 M = 1080
Mass of Container M = 1080 g
Answer(s): (a) 1760 g; (b) 1080 g