Container Y and Container Z were filled completely with curry powder. The total mass of ¹₄ of the curry powder in Container Z and ¹₁₃ of the curry powder in Container Y was 600 g. If ³₁₃ of the curry powder in Container Y was poured out, the total mass of the curry powder in both containers became 3.48 kg. How much curry powder was in

1. Container Y in grams?
2. Container Z in grams?

(a)
Let the mass of the curry powder in Container Z be Z.
Let the mass of the curry powder in Container Y be Y.

¹₄ Z + ¹₁₃ Y = 600 --- (1)

Fraction of the curry powder left in Container Y after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.48 kg = 3480 g

1 Z + ¹⁰₁₃ Y = 3480
1 Z = 3480 - ¹⁰₁₃ Y --- (2)

Make Z the same.

(1)_x4
⁴₄ Z + ⁴₁₃ Y = 2400
1 Z + ⁴₁₃ Y = 2400
1 Z = 2400 - ⁴₁₃ Y --- (3)

(3) = (2) 
2400 - ⁴₁₃ Y = 3480 - ¹⁰₁₃ X
¹⁰₁₃ Y - ⁴₁₃ Y = 3480 - 2400
⁶₁₃ Y = 1080
¹₁₃ Y = 1080 ÷ 6 = 180

¹³₁₃ Y = 13 x 180 = 2340

1 Y = 2340

Mass of Container Y = 2340 g

(b)
From (1)
¹₄ Z + 180 = 600
¹₄ Z = 600 - 180 = 420

⁴₄ Z = 4 x 420 = 1680

1 Z = 1680

Mass of Container Z = 1680 g

Answer(s): (a) 2340 g; (b) 1680 g