Container G and Container H were filled completely with pepper. The total mass of ¹₆ of the pepper in Container H and ¹₁₃ of the pepper in Container G was 400 g. If ⁴₁₃ of the pepper in Container G was poured out, the total mass of the pepper in both containers became 2.7 kg. How much pepper was in

1. Container G in grams?
2. Container H in grams?

(a)
Let the mass of the pepper in Container H be H.
Let the mass of the pepper in Container G be G.

¹₆ H + ¹₁₃ G = 400 --- (1)

Fraction of the pepper left in Container G after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
2.7 kg = 2700 g

1 H + ⁹₁₃ G = 2700
1 H = 2700 - ⁹₁₃ G --- (2)

Make H the same.

(1)_x6
⁶₆ H + ⁶₁₃ G = 2400
1 H + ⁶₁₃ G = 2400
1 H = 2400 - ⁶₁₃ G --- (3)

(3) = (2) 
2400 - ⁶₁₃ G = 2700 - ⁹₁₃ X
⁹₁₃ G - ⁶₁₃ G = 2700 - 2400
³₁₃ G = 300
¹₁₃ G = 300 ÷ 3 = 100

¹³₁₃ G = 13 x 100 = 1300

1 G = 1300

Mass of Container G = 1300 g

(b)
From (1)
¹₆ H + 100 = 400
¹₆ H = 400 - 100 = 300

⁶₆ H = 6 x 300 = 1800

1 H = 1800

Mass of Container H = 1800 g

Answer(s): (a) 1300 g; (b) 1800 g