Container S and Container T were filled completely with rice flour. The total mass of ¹₆ of the rice flour in Container T and ¹₁₃ of the rice flour in Container S was 560 g. If ²₁₃ of the rice flour in Container S was poured out, the total mass of the rice flour in both containers became 3.91 kg. How much rice flour was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the rice flour in Container T be T.
Let the mass of the rice flour in Container S be S.

¹₆ T + ¹₁₃ S = 560 --- (1)

Fraction of the rice flour left in Container S after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
3.91 kg = 3910 g

1 T + ¹¹₁₃ S = 3910
1 T = 3910 - ¹¹₁₃ S --- (2)

Make T the same.

(1)_x6
⁶₆ T + ⁶₁₃ S = 3360
1 T + ⁶₁₃ S = 3360
1 T = 3360 - ⁶₁₃ S --- (3)

(3) = (2) 
3360 - ⁶₁₃ S = 3910 - ¹¹₁₃ X
¹¹₁₃ S - ⁶₁₃ S = 3910 - 3360
⁵₁₃ S = 550
¹₁₃ S = 550 ÷ 5 = 110

¹³₁₃ S = 13 x 110 = 1430

1 S = 1430

Mass of Container S = 1430 g

(b)
From (1)
¹₆ T + 110 = 560
¹₆ T = 560 - 110 = 450

⁶₆ T = 6 x 450 = 2700

1 T = 2700

Mass of Container T = 2700 g

Answer(s): (a) 1430 g; (b) 2700 g