Container K and Container L were filled completely with flour. The total mass of
16 of the flour in Container L and
113 of the flour in Container K was 580 g. If
213 of the flour in Container K was poured out, the total mass of the flour in both containers became 4.18 kg. How much flour was in
- Container K in grams?
- Container L in grams?
(a)
Let the mass of the flour in Container L be L.
Let the mass of the flour in Container K be K.
16 L +
113 K = 580 --- (1)
Fraction of the flour left in Container K after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
4.18 kg = 4180 g
1 L +
1113 K = 4180
1 L = 4180 -
1113 K --- (2)
Make L the same.
(1)
x6 66 L +
613 K = 3480
1 L +
613 K = 3480
1 L = 3480 -
613 K --- (3)
(3) = (2)
3480 -
613 K = 4180 -
1113 X
1113 K -
613 K = 4180 - 3480
513 K = 700
113 K = 700 ÷ 5 = 140
1313 K = 13 x 140 = 1820
1 K = 1820
Mass of Container K = 1820 g
(b)
From (1)
16 L + 140 = 580
16 L = 580 - 140 = 440
66 L = 6 x 440 = 2640
1 L = 2640
Mass of Container L = 2640 g
Answer(s): (a) 1820 g; (b) 2640 g