Container S and Container T were filled completely with chicken powder. The total mass of
14 of the chicken powder in Container T and
113 of the chicken powder in Container S was 570 g. If
213 of the chicken powder in Container S was poured out, the total mass of the chicken powder in both containers became 3.26 kg. How much chicken powder was in
- Container S in grams?
- Container T in grams?
(a)
Let the mass of the chicken powder in Container T be T.
Let the mass of the chicken powder in Container S be S.
14 T +
113 S = 570 --- (1)
Fraction of the chicken powder left in Container S after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
3.26 kg = 3260 g
1 T +
1113 S = 3260
1 T = 3260 -
1113 S --- (2)
Make T the same.
(1)
x4 44 T +
413 S = 2280
1 T +
413 S = 2280
1 T = 2280 -
413 S --- (3)
(3) = (2)
2280 -
413 S = 3260 -
1113 X
1113 S -
413 S = 3260 - 2280
713 S = 980
113 S = 980 ÷ 7 = 140
1313 S = 13 x 140 = 1820
1 S = 1820
Mass of Container S = 1820 g
(b)
From (1)
14 T + 140 = 570
14 T = 570 - 140 = 430
44 T = 4 x 430 = 1720
1 T = 1720
Mass of Container T = 1720 g
Answer(s): (a) 1820 g; (b) 1720 g