Container N and Container P were filled completely with chicken powder. The total mass of ¹₈ of the chicken powder in Container P and ¹₁₃ of the chicken powder in Container N was 510 g. If ³₁₃ of the chicken powder in Container N was poured out, the total mass of the chicken powder in both containers became 4.28 kg. How much chicken powder was in

1. Container N in grams?
2. Container P in grams?

(a)
Let the mass of the chicken powder in Container P be P.
Let the mass of the chicken powder in Container N be N.

¹₈ P + ¹₁₃ N = 510 --- (1)

Fraction of the chicken powder left in Container N after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
4.28 kg = 4280 g

1 P + ¹⁰₁₃ N = 4280
1 P = 4280 - ¹⁰₁₃ N --- (2)

Make P the same.

(1)_x8
⁸₈ P + ⁸₁₃ N = 4080
1 P + ⁸₁₃ N = 4080
1 P = 4080 - ⁸₁₃ N --- (3)

(3) = (2) 
4080 - ⁸₁₃ N = 4280 - ¹⁰₁₃ X
¹⁰₁₃ N - ⁸₁₃ N = 4280 - 4080
²₁₃ N = 200
¹₁₃ N = 200 ÷ 2 = 100

¹³₁₃ N = 13 x 100 = 1300

1 N = 1300

Mass of Container N = 1300 g

(b)
From (1)
¹₈ P + 100 = 510
¹₈ P = 510 - 100 = 410

⁸₈ P = 8 x 410 = 3280

1 P = 3280

Mass of Container P = 3280 g

Answer(s): (a) 1300 g; (b) 3280 g