Container B and Container C were filled completely with chicken powder. The total mass of
13 of the chicken powder in Container C and
113 of the chicken powder in Container B was 520 g. If
313 of the chicken powder in Container B was poured out, the total mass of the chicken powder in both containers became 2.61 kg. How much chicken powder was in
- Container B in grams?
- Container C in grams?
(a)
Let the mass of the chicken powder in Container C be C.
Let the mass of the chicken powder in Container B be B.
13 C +
113 B = 520 --- (1)
Fraction of the chicken powder left in Container B after
313 of it was poured out
= 1 -
313 =
1013 1 kg = 1000 g
2.61 kg = 2610 g
1 C +
1013 B = 2610
1 C = 2610 -
1013 B --- (2)
Make C the same.
(1)
x3 33 C +
313 B = 1560
1 C +
313 B = 1560
1 C = 1560 -
313 B --- (3)
(3) = (2)
1560 -
313 B = 2610 -
1013 X
1013 B -
313 B = 2610 - 1560
713 B = 1050
113 B = 1050 ÷ 7 = 150
1313 B = 13 x 150 = 1950
1 B = 1950
Mass of Container B = 1950 g
(b)
From (1)
13 C + 150 = 520
13 C = 520 - 150 = 370
33 C = 3 x 370 = 1110
1 C = 1110
Mass of Container C = 1110 g
Answer(s): (a) 1950 g; (b) 1110 g