Container H and Container J were filled completely with flour. The total mass of ¹₃ of the flour in Container J and ¹₁₁ of the flour in Container H was 560 g. If ³₁₁ of the flour in Container H was poured out, the total mass of the flour in both containers became 2.43 kg. How much flour was in

1. Container H in grams?
2. Container J in grams?

(a)
Let the mass of the flour in Container J be J.
Let the mass of the flour in Container H be H.

¹₃ J + ¹₁₁ H = 560 --- (1)

Fraction of the flour left in Container H after ³₁₁ of it was poured out
= 1 - ³₁₁
= ⁸₁₁

1 kg = 1000 g
2.43 kg = 2430 g

1 J + ⁸₁₁ H = 2430
1 J = 2430 - ⁸₁₁ H --- (2)

Make J the same.

(1)_x3
³₃ J + ³₁₁ H = 1680
1 J + ³₁₁ H = 1680
1 J = 1680 - ³₁₁ H --- (3)

(3) = (2) 
1680 - ³₁₁ H = 2430 - ⁸₁₁ X
⁸₁₁ H - ³₁₁ H = 2430 - 1680
⁵₁₁ H = 750
¹₁₁ H = 750 ÷ 5 = 150

¹¹₁₁ H = 11 x 150 = 1650

1 H = 1650

Mass of Container H = 1650 g

(b)
From (1)
¹₃ J + 150 = 560
¹₃ J = 560 - 150 = 410

³₃ J = 3 x 410 = 1230

1 J = 1230

Mass of Container J = 1230 g

Answer(s): (a) 1650 g; (b) 1230 g