Container T and Container U were filled completely with bread flour. The total mass of
15 of the bread flour in Container U and
111 of the bread flour in Container T was 540 g. If
411 of the bread flour in Container T was poured out, the total mass of the bread flour in both containers became 2.92 kg. How much bread flour was in
- Container T in grams?
- Container U in grams?
(a)
Let the mass of the bread flour in Container U be U.
Let the mass of the bread flour in Container T be T.
15 U +
111 T = 540 --- (1)
Fraction of the bread flour left in Container T after
411 of it was poured out
= 1 -
411 =
711 1 kg = 1000 g
2.92 kg = 2920 g
1 U +
711 T = 2920
1 U = 2920 -
711 T --- (2)
Make U the same.
(1)
x5 55 U +
511 T = 2700
1 U +
511 T = 2700
1 U = 2700 -
511 T --- (3)
(3) = (2)
2700 -
511 T = 2920 -
711 X
711 T -
511 T = 2920 - 2700
211 T = 220
111 T = 220 ÷ 2 = 110
1111 T = 11 x 110 = 1210
1 T = 1210
Mass of Container T = 1210 g
(b)
From (1)
15 U + 110 = 540
15 U = 540 - 110 = 430
55 U = 5 x 430 = 2150
1 U = 2150
Mass of Container U = 2150 g
Answer(s): (a) 1210 g; (b) 2150 g