Container V and Container W were filled completely with rice flour. The total mass of ¹₃ of the rice flour in Container W and ¹₁₁ of the rice flour in Container V was 500 g. If ⁵₁₁ of the rice flour in Container V was poured out, the total mass of the rice flour in both containers became 2.1 kg. How much rice flour was in

1. Container V in grams?
2. Container W in grams?

(a)
Let the mass of the rice flour in Container W be W.
Let the mass of the rice flour in Container V be V.

¹₃ W + ¹₁₁ V = 500 --- (1)

Fraction of the rice flour left in Container V after ⁵₁₁ of it was poured out
= 1 - ⁵₁₁
= ⁶₁₁

1 kg = 1000 g
2.1 kg = 2100 g

1 W + ⁶₁₁ V = 2100
1 W = 2100 - ⁶₁₁ V --- (2)

Make W the same.

(1)_x3
³₃ W + ³₁₁ V = 1500
1 W + ³₁₁ V = 1500
1 W = 1500 - ³₁₁ V --- (3)

(3) = (2) 
1500 - ³₁₁ V = 2100 - ⁶₁₁ X
⁶₁₁ V - ³₁₁ V = 2100 - 1500
³₁₁ V = 600
¹₁₁ V = 600 ÷ 3 = 200

¹¹₁₁ V = 11 x 200 = 2200

1 V = 2200

Mass of Container V = 2200 g

(b)
From (1)
¹₃ W + 200 = 500
¹₃ W = 500 - 200 = 300

³₃ W = 3 x 300 = 900

1 W = 900

Mass of Container W = 900 g

Answer(s): (a) 2200 g; (b) 900 g