Container N and Container P were filled completely with sugar. The total mass of ¹₆ of the sugar in Container P and ¹₁₃ of the sugar in Container N was 480 g. If ⁴₁₃ of the sugar in Container N was poured out, the total mass of the sugar in both containers became 3.3 kg. How much sugar was in

1. Container N in grams?
2. Container P in grams?

(a)
Let the mass of the sugar in Container P be P.
Let the mass of the sugar in Container N be N.

¹₆ P + ¹₁₃ N = 480 --- (1)

Fraction of the sugar left in Container N after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
3.3 kg = 3300 g

1 P + ⁹₁₃ N = 3300
1 P = 3300 - ⁹₁₃ N --- (2)

Make P the same.

(1)_x6
⁶₆ P + ⁶₁₃ N = 2880
1 P + ⁶₁₃ N = 2880
1 P = 2880 - ⁶₁₃ N --- (3)

(3) = (2) 
2880 - ⁶₁₃ N = 3300 - ⁹₁₃ X
⁹₁₃ N - ⁶₁₃ N = 3300 - 2880
³₁₃ N = 420
¹₁₃ N = 420 ÷ 3 = 140

¹³₁₃ N = 13 x 140 = 1820

1 N = 1820

Mass of Container N = 1820 g

(b)
From (1)
¹₆ P + 140 = 480
¹₆ P = 480 - 140 = 340

⁶₆ P = 6 x 340 = 2040

1 P = 2040

Mass of Container P = 2040 g

Answer(s): (a) 1820 g; (b) 2040 g