Container A and Container B were filled completely with chicken powder. The total mass of
17 of the chicken powder in Container B and
113 of the chicken powder in Container A was 570 g. If
413 of the chicken powder in Container A was poured out, the total mass of the chicken powder in both containers became 4.39 kg. How much chicken powder was in
- Container A in grams?
- Container B in grams?
(a)
Let the mass of the chicken powder in Container B be B.
Let the mass of the chicken powder in Container A be A.
17 B +
113 A = 570 --- (1)
Fraction of the chicken powder left in Container A after
413 of it was poured out
= 1 -
413 =
913 1 kg = 1000 g
4.39 kg = 4390 g
1 B +
913 A = 4390
1 B = 4390 -
913 A --- (2)
Make B the same.
(1)
x7 77 B +
713 A = 3990
1 B +
713 A = 3990
1 B = 3990 -
713 A --- (3)
(3) = (2)
3990 -
713 A = 4390 -
913 X
913 A -
713 A = 4390 - 3990
213 A = 400
113 A = 400 ÷ 2 = 200
1313 A = 13 x 200 = 2600
1 A = 2600
Mass of Container A = 2600 g
(b)
From (1)
17 B + 200 = 570
17 B = 570 - 200 = 370
77 B = 7 x 370 = 2590
1 B = 2590
Mass of Container B = 2590 g
Answer(s): (a) 2600 g; (b) 2590 g