Container B and Container C were filled completely with rice flour. The total mass of
14 of the rice flour in Container C and
113 of the rice flour in Container B was 620 g. If
313 of the rice flour in Container B was poured out, the total mass of the rice flour in both containers became 3.5 kg. How much rice flour was in
- Container B in grams?
- Container C in grams?
(a)
Let the mass of the rice flour in Container C be C.
Let the mass of the rice flour in Container B be B.
14 C +
113 B = 620 --- (1)
Fraction of the rice flour left in Container B after
313 of it was poured out
= 1 -
313 =
1013 1 kg = 1000 g
3.5 kg = 3500 g
1 C +
1013 B = 3500
1 C = 3500 -
1013 B --- (2)
Make C the same.
(1)
x4 44 C +
413 B = 2480
1 C +
413 B = 2480
1 C = 2480 -
413 B --- (3)
(3) = (2)
2480 -
413 B = 3500 -
1013 X
1013 B -
413 B = 3500 - 2480
613 B = 1020
113 B = 1020 ÷ 6 = 170
1313 B = 13 x 170 = 2210
1 B = 2210
Mass of Container B = 2210 g
(b)
From (1)
14 C + 170 = 620
14 C = 620 - 170 = 450
44 C = 4 x 450 = 1800
1 C = 1800
Mass of Container C = 1800 g
Answer(s): (a) 2210 g; (b) 1800 g