Container L and Container M were filled completely with rice flour. The total mass of ¹₆ of the rice flour in Container M and ¹₁₃ of the rice flour in Container L was 540 g. If ³₁₃ of the rice flour in Container L was poured out, the total mass of the rice flour in both containers became 3.76 kg. How much rice flour was in

1. Container L in grams?
2. Container M in grams?

(a)
Let the mass of the rice flour in Container M be M.
Let the mass of the rice flour in Container L be L.

¹₆ M + ¹₁₃ L = 540 --- (1)

Fraction of the rice flour left in Container L after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.76 kg = 3760 g

1 M + ¹⁰₁₃ L = 3760
1 M = 3760 - ¹⁰₁₃ L --- (2)

Make M the same.

(1)_x6
⁶₆ M + ⁶₁₃ L = 3240
1 M + ⁶₁₃ L = 3240
1 M = 3240 - ⁶₁₃ L --- (3)

(3) = (2) 
3240 - ⁶₁₃ L = 3760 - ¹⁰₁₃ X
¹⁰₁₃ L - ⁶₁₃ L = 3760 - 3240
⁴₁₃ L = 520
¹₁₃ L = 520 ÷ 4 = 130

¹³₁₃ L = 13 x 130 = 1690

1 L = 1690

Mass of Container L = 1690 g

(b)
From (1)
¹₆ M + 130 = 540
¹₆ M = 540 - 130 = 410

⁶₆ M = 6 x 410 = 2460

1 M = 2460

Mass of Container M = 2460 g

Answer(s): (a) 1690 g; (b) 2460 g