Container T and Container U were filled completely with bread flour. The total mass of ¹₅ of the bread flour in Container U and ¹₁₃ of the bread flour in Container T was 410 g. If ²₁₃ of the bread flour in Container T was poured out, the total mass of the bread flour in both containers became 2.65 kg. How much bread flour was in

1. Container T in grams?
2. Container U in grams?

(a)
Let the mass of the bread flour in Container U be U.
Let the mass of the bread flour in Container T be T.

¹₅ U + ¹₁₃ T = 410 --- (1)

Fraction of the bread flour left in Container T after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
2.65 kg = 2650 g

1 U + ¹¹₁₃ T = 2650
1 U = 2650 - ¹¹₁₃ T --- (2)

Make U the same.

(1)_x5
⁵₅ U + ⁵₁₃ T = 2050
1 U + ⁵₁₃ T = 2050
1 U = 2050 - ⁵₁₃ T --- (3)

(3) = (2) 
2050 - ⁵₁₃ T = 2650 - ¹¹₁₃ X
¹¹₁₃ T - ⁵₁₃ T = 2650 - 2050
⁶₁₃ T = 600
¹₁₃ T = 600 ÷ 6 = 100

¹³₁₃ T = 13 x 100 = 1300

1 T = 1300

Mass of Container T = 1300 g

(b)
From (1)
¹₅ U + 100 = 410
¹₅ U = 410 - 100 = 310

⁵₅ U = 5 x 310 = 1550

1 U = 1550

Mass of Container U = 1550 g

Answer(s): (a) 1300 g; (b) 1550 g