Container T and Container U were filled completely with rice flour. The total mass of
13 of the rice flour in Container U and
111 of the rice flour in Container T was 480 g. If
511 of the rice flour in Container T was poured out, the total mass of the rice flour in both containers became 1.83 kg. How much rice flour was in
- Container T in grams?
- Container U in grams?
(a)
Let the mass of the rice flour in Container U be U.
Let the mass of the rice flour in Container T be T.
13 U +
111 T = 480 --- (1)
Fraction of the rice flour left in Container T after
511 of it was poured out
= 1 -
511 =
611 1 kg = 1000 g
1.83 kg = 1830 g
1 U +
611 T = 1830
1 U = 1830 -
611 T --- (2)
Make U the same.
(1)
x3 33 U +
311 T = 1440
1 U +
311 T = 1440
1 U = 1440 -
311 T --- (3)
(3) = (2)
1440 -
311 T = 1830 -
611 X
611 T -
311 T = 1830 - 1440
311 T = 390
111 T = 390 ÷ 3 = 130
1111 T = 11 x 130 = 1430
1 T = 1430
Mass of Container T = 1430 g
(b)
From (1)
13 U + 130 = 480
13 U = 480 - 130 = 350
33 U = 3 x 350 = 1050
1 U = 1050
Mass of Container U = 1050 g
Answer(s): (a) 1430 g; (b) 1050 g