Container G and Container H were filled completely with sugar. The total mass of
17 of the sugar in Container H and
113 of the sugar in Container G was 600 g. If
213 of the sugar in Container G was poured out, the total mass of the sugar in both containers became 4.84 kg. How much sugar was in
- Container G in grams?
- Container H in grams?
(a)
Let the mass of the sugar in Container H be H.
Let the mass of the sugar in Container G be G.
17 H +
113 G = 600 --- (1)
Fraction of the sugar left in Container G after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
4.84 kg = 4840 g
1 H +
1113 G = 4840
1 H = 4840 -
1113 G --- (2)
Make H the same.
(1)
x7 77 H +
713 G = 4200
1 H +
713 G = 4200
1 H = 4200 -
713 G --- (3)
(3) = (2)
4200 -
713 G = 4840 -
1113 X
1113 G -
713 G = 4840 - 4200
413 G = 640
113 G = 640 ÷ 4 = 160
1313 G = 13 x 160 = 2080
1 G = 2080
Mass of Container G = 2080 g
(b)
From (1)
17 H + 160 = 600
17 H = 600 - 160 = 440
77 H = 7 x 440 = 3080
1 H = 3080
Mass of Container H = 3080 g
Answer(s): (a) 2080 g; (b) 3080 g