Container K and Container L were filled completely with bread flour. The total mass of ¹₃ of the bread flour in Container L and ¹₁₁ of the bread flour in Container K was 550 g. If ²₁₁ of the bread flour in Container K was poured out, the total mass of the bread flour in both containers became 2.61 kg. How much bread flour was in

1. Container K in grams?
2. Container L in grams?

(a)
Let the mass of the bread flour in Container L be L.
Let the mass of the bread flour in Container K be K.

¹₃ L + ¹₁₁ K = 550 --- (1)

Fraction of the bread flour left in Container K after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
2.61 kg = 2610 g

1 L + ⁹₁₁ K = 2610
1 L = 2610 - ⁹₁₁ K --- (2)

Make L the same.

(1)_x3
³₃ L + ³₁₁ K = 1650
1 L + ³₁₁ K = 1650
1 L = 1650 - ³₁₁ K --- (3)

(3) = (2) 
1650 - ³₁₁ K = 2610 - ⁹₁₁ X
⁹₁₁ K - ³₁₁ K = 2610 - 1650
⁶₁₁ K = 960
¹₁₁ K = 960 ÷ 6 = 160

¹¹₁₁ K = 11 x 160 = 1760

1 K = 1760

Mass of Container K = 1760 g

(b)
From (1)
¹₃ L + 160 = 550
¹₃ L = 550 - 160 = 390

³₃ L = 3 x 390 = 1170

1 L = 1170

Mass of Container L = 1170 g

Answer(s): (a) 1760 g; (b) 1170 g