Container L and Container M were filled completely with chilli powder. The total mass of ¹₃ of the chilli powder in Container M and ¹₁₃ of the chilli powder in Container L was 510 g. If ⁴₁₃ of the chilli powder in Container L was poured out, the total mass of the chilli powder in both containers became 2.61 kg. How much chilli powder was in

1. Container L in grams?
2. Container M in grams?

(a)
Let the mass of the chilli powder in Container M be M.
Let the mass of the chilli powder in Container L be L.

¹₃ M + ¹₁₃ L = 510 --- (1)

Fraction of the chilli powder left in Container L after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
2.61 kg = 2610 g

1 M + ⁹₁₃ L = 2610
1 M = 2610 - ⁹₁₃ L --- (2)

Make M the same.

(1)_x3
³₃ M + ³₁₃ L = 1530
1 M + ³₁₃ L = 1530
1 M = 1530 - ³₁₃ L --- (3)

(3) = (2) 
1530 - ³₁₃ L = 2610 - ⁹₁₃ X
⁹₁₃ L - ³₁₃ L = 2610 - 1530
⁶₁₃ L = 1080
¹₁₃ L = 1080 ÷ 6 = 180

¹³₁₃ L = 13 x 180 = 2340

1 L = 2340

Mass of Container L = 2340 g

(b)
From (1)
¹₃ M + 180 = 510
¹₃ M = 510 - 180 = 330

³₃ M = 3 x 330 = 990

1 M = 990

Mass of Container M = 990 g

Answer(s): (a) 2340 g; (b) 990 g