Container X and Container Y were filled completely with bread flour. The total mass of
15 of the bread flour in Container Y and
113 of the bread flour in Container X was 620 g. If
313 of the bread flour in Container X was poured out, the total mass of the bread flour in both containers became 4 kg. How much bread flour was in
- Container X in grams?
- Container Y in grams?
(a)
Let the mass of the bread flour in Container Y be Y.
Let the mass of the bread flour in Container X be X.
15 Y +
113 X = 620 --- (1)
Fraction of the bread flour left in Container X after
313 of it was poured out
= 1 -
313 =
1013 1 kg = 1000 g
4 kg = 4000 g
1 Y +
1013 X = 4000
1 Y = 4000 -
1013 X --- (2)
Make Y the same.
(1)
x5 55 Y +
513 X = 3100
1 Y +
513 X = 3100
1 Y = 3100 -
513 X --- (3)
(3) = (2)
3100 -
513 X = 4000 -
1013 X
1013 X -
513 X = 4000 - 3100
513 X = 900
113 X = 900 ÷ 5 = 180
1313 X = 13 x 180 = 2340
1 X = 2340
Mass of Container X = 2340 g
(b)
From (1)
15 Y + 180 = 620
15 Y = 620 - 180 = 440
55 Y = 5 x 440 = 2200
1 Y = 2200
Mass of Container Y = 2200 g
Answer(s): (a) 2340 g; (b) 2200 g