Container M and Container N were filled completely with curry powder. The total mass of ¹₃ of the curry powder in Container N and ¹₁₃ of the curry powder in Container M was 570 g. If ²₁₃ of the curry powder in Container M was poured out, the total mass of the curry powder in both containers became 3.07 kg. How much curry powder was in

1. Container M in grams?
2. Container N in grams?

(a)
Let the mass of the curry powder in Container N be N.
Let the mass of the curry powder in Container M be M.

¹₃ N + ¹₁₃ M = 570 --- (1)

Fraction of the curry powder left in Container M after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
3.07 kg = 3070 g

1 N + ¹¹₁₃ M = 3070
1 N = 3070 - ¹¹₁₃ M --- (2)

Make N the same.

(1)_x3
³₃ N + ³₁₃ M = 1710
1 N + ³₁₃ M = 1710
1 N = 1710 - ³₁₃ M --- (3)

(3) = (2) 
1710 - ³₁₃ M = 3070 - ¹¹₁₃ X
¹¹₁₃ M - ³₁₃ M = 3070 - 1710
⁸₁₃ M = 1360
¹₁₃ M = 1360 ÷ 8 = 170

¹³₁₃ M = 13 x 170 = 2210

1 M = 2210

Mass of Container M = 2210 g

(b)
From (1)
¹₃ N + 170 = 570
¹₃ N = 570 - 170 = 400

³₃ N = 3 x 400 = 1200

1 N = 1200

Mass of Container N = 1200 g

Answer(s): (a) 2210 g; (b) 1200 g