Container E and Container F were filled completely with chicken powder. The total mass of ¹₃ of the chicken powder in Container F and ¹₁₃ of the chicken powder in Container E was 470 g. If ²₁₃ of the chicken powder in Container E was poured out, the total mass of the chicken powder in both containers became 2.45 kg. How much chicken powder was in

1. Container E in grams?
2. Container F in grams?

(a)
Let the mass of the chicken powder in Container F be F.
Let the mass of the chicken powder in Container E be E.

¹₃ F + ¹₁₃ E = 470 --- (1)

Fraction of the chicken powder left in Container E after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
2.45 kg = 2450 g

1 F + ¹¹₁₃ E = 2450
1 F = 2450 - ¹¹₁₃ E --- (2)

Make F the same.

(1)_x3
³₃ F + ³₁₃ E = 1410
1 F + ³₁₃ E = 1410
1 F = 1410 - ³₁₃ E --- (3)

(3) = (2) 
1410 - ³₁₃ E = 2450 - ¹¹₁₃ X
¹¹₁₃ E - ³₁₃ E = 2450 - 1410
⁸₁₃ E = 1040
¹₁₃ E = 1040 ÷ 8 = 130

¹³₁₃ E = 13 x 130 = 1690

1 E = 1690

Mass of Container E = 1690 g

(b)
From (1)
¹₃ F + 130 = 470
¹₃ F = 470 - 130 = 340

³₃ F = 3 x 340 = 1020

1 F = 1020

Mass of Container F = 1020 g

Answer(s): (a) 1690 g; (b) 1020 g