Container T and Container U were filled completely with flour. The total mass of ¹₆ of the flour in Container U and ¹₁₃ of the flour in Container T was 580 g. If ³₁₃ of the flour in Container T was poured out, the total mass of the flour in both containers became 4.08 kg. How much flour was in

1. Container T in grams?
2. Container U in grams?

(a)
Let the mass of the flour in Container U be U.
Let the mass of the flour in Container T be T.

¹₆ U + ¹₁₃ T = 580 --- (1)

Fraction of the flour left in Container T after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
4.08 kg = 4080 g

1 U + ¹⁰₁₃ T = 4080
1 U = 4080 - ¹⁰₁₃ T --- (2)

Make U the same.

(1)_x6
⁶₆ U + ⁶₁₃ T = 3480
1 U + ⁶₁₃ T = 3480
1 U = 3480 - ⁶₁₃ T --- (3)

(3) = (2) 
3480 - ⁶₁₃ T = 4080 - ¹⁰₁₃ X
¹⁰₁₃ T - ⁶₁₃ T = 4080 - 3480
⁴₁₃ T = 600
¹₁₃ T = 600 ÷ 4 = 150

¹³₁₃ T = 13 x 150 = 1950

1 T = 1950

Mass of Container T = 1950 g

(b)
From (1)
¹₆ U + 150 = 580
¹₆ U = 580 - 150 = 430

⁶₆ U = 6 x 430 = 2580

1 U = 2580

Mass of Container U = 2580 g

Answer(s): (a) 1950 g; (b) 2580 g