Container R and Container S were filled completely with rice flour. The total mass of ¹₆ of the rice flour in Container S and ¹₁₁ of the rice flour in Container R was 560 g. If ³₁₁ of the rice flour in Container R was poured out, the total mass of the rice flour in both containers became 3.58 kg. How much rice flour was in

1. Container R in grams?
2. Container S in grams?

(a)
Let the mass of the rice flour in Container S be S.
Let the mass of the rice flour in Container R be R.

¹₆ S + ¹₁₁ R = 560 --- (1)

Fraction of the rice flour left in Container R after ³₁₁ of it was poured out
= 1 - ³₁₁
= ⁸₁₁

1 kg = 1000 g
3.58 kg = 3580 g

1 S + ⁸₁₁ R = 3580
1 S = 3580 - ⁸₁₁ R --- (2)

Make S the same.

(1)_x6
⁶₆ S + ⁶₁₁ R = 3360
1 S + ⁶₁₁ R = 3360
1 S = 3360 - ⁶₁₁ R --- (3)

(3) = (2) 
3360 - ⁶₁₁ R = 3580 - ⁸₁₁ X
⁸₁₁ R - ⁶₁₁ R = 3580 - 3360
²₁₁ R = 220
¹₁₁ R = 220 ÷ 2 = 110

¹¹₁₁ R = 11 x 110 = 1210

1 R = 1210

Mass of Container R = 1210 g

(b)
From (1)
¹₆ S + 110 = 560
¹₆ S = 560 - 110 = 450

⁶₆ S = 6 x 450 = 2700

1 S = 2700

Mass of Container S = 2700 g

Answer(s): (a) 1210 g; (b) 2700 g