Container J and Container K were filled completely with flour. The total mass of
14 of the flour in Container K and
113 of the flour in Container J was 500 g. If
213 of the flour in Container J was poured out, the total mass of the flour in both containers became 3.05 kg. How much flour was in
- Container J in grams?
- Container K in grams?
(a)
Let the mass of the flour in Container K be K.
Let the mass of the flour in Container J be J.
14 K +
113 J = 500 --- (1)
Fraction of the flour left in Container J after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
3.05 kg = 3050 g
1 K +
1113 J = 3050
1 K = 3050 -
1113 J --- (2)
Make K the same.
(1)
x4 44 K +
413 J = 2000
1 K +
413 J = 2000
1 K = 2000 -
413 J --- (3)
(3) = (2)
2000 -
413 J = 3050 -
1113 X
1113 J -
413 J = 3050 - 2000
713 J = 1050
113 J = 1050 ÷ 7 = 150
1313 J = 13 x 150 = 1950
1 J = 1950
Mass of Container J = 1950 g
(b)
From (1)
14 K + 150 = 500
14 K = 500 - 150 = 350
44 K = 4 x 350 = 1400
1 K = 1400
Mass of Container K = 1400 g
Answer(s): (a) 1950 g; (b) 1400 g