Container V and Container W were filled completely with chicken powder. The total mass of ¹₄ of the chicken powder in Container W and ¹₁₃ of the chicken powder in Container V was 520 g. If ⁵₁₃ of the chicken powder in Container V was poured out, the total mass of the chicken powder in both containers became 2.56 kg. How much chicken powder was in

1. Container V in grams?
2. Container W in grams?

(a)
Let the mass of the chicken powder in Container W be W.
Let the mass of the chicken powder in Container V be V.

¹₄ W + ¹₁₃ V = 520 --- (1)

Fraction of the chicken powder left in Container V after ⁵₁₃ of it was poured out
= 1 - ⁵₁₃
= ⁸₁₃

1 kg = 1000 g
2.56 kg = 2560 g

1 W + ⁸₁₃ V = 2560
1 W = 2560 - ⁸₁₃ V --- (2)

Make W the same.

(1)_x4
⁴₄ W + ⁴₁₃ V = 2080
1 W + ⁴₁₃ V = 2080
1 W = 2080 - ⁴₁₃ V --- (3)

(3) = (2) 
2080 - ⁴₁₃ V = 2560 - ⁸₁₃ X
⁸₁₃ V - ⁴₁₃ V = 2560 - 2080
⁴₁₃ V = 480
¹₁₃ V = 480 ÷ 4 = 120

¹³₁₃ V = 13 x 120 = 1560

1 V = 1560

Mass of Container V = 1560 g

(b)
From (1)
¹₄ W + 120 = 520
¹₄ W = 520 - 120 = 400

⁴₄ W = 4 x 400 = 1600

1 W = 1600

Mass of Container W = 1600 g

Answer(s): (a) 1560 g; (b) 1600 g