Container A and Container B were filled completely with rice flour. The total mass of ¹₆ of the rice flour in Container B and ¹₁₁ of the rice flour in Container A was 510 g. If ³₁₁ of the rice flour in Container A was poured out, the total mass of the rice flour in both containers became 3.32 kg. How much rice flour was in

1. Container A in grams?
2. Container B in grams?

(a)
Let the mass of the rice flour in Container B be B.
Let the mass of the rice flour in Container A be A.

¹₆ B + ¹₁₁ A = 510 --- (1)

Fraction of the rice flour left in Container A after ³₁₁ of it was poured out
= 1 - ³₁₁
= ⁸₁₁

1 kg = 1000 g
3.32 kg = 3320 g

1 B + ⁸₁₁ A = 3320
1 B = 3320 - ⁸₁₁ A --- (2)

Make B the same.

(1)_x6
⁶₆ B + ⁶₁₁ A = 3060
1 B + ⁶₁₁ A = 3060
1 B = 3060 - ⁶₁₁ A --- (3)

(3) = (2) 
3060 - ⁶₁₁ A = 3320 - ⁸₁₁ X
⁸₁₁ A - ⁶₁₁ A = 3320 - 3060
²₁₁ A = 260
¹₁₁ A = 260 ÷ 2 = 130

¹¹₁₁ A = 11 x 130 = 1430

1 A = 1430

Mass of Container A = 1430 g

(b)
From (1)
¹₆ B + 130 = 510
¹₆ B = 510 - 130 = 380

⁶₆ B = 6 x 380 = 2280

1 B = 2280

Mass of Container B = 2280 g

Answer(s): (a) 1430 g; (b) 2280 g