Container Y and Container Z were filled completely with curry powder. The total mass of ¹₈ of the curry powder in Container Z and ¹₁₃ of the curry powder in Container Y was 560 g. If ²₁₃ of the curry powder in Container Y was poured out, the total mass of the curry powder in both containers became 4.96 kg. How much curry powder was in

1. Container Y in grams?
2. Container Z in grams?

(a)
Let the mass of the curry powder in Container Z be Z.
Let the mass of the curry powder in Container Y be Y.

¹₈ Z + ¹₁₃ Y = 560 --- (1)

Fraction of the curry powder left in Container Y after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
4.96 kg = 4960 g

1 Z + ¹¹₁₃ Y = 4960
1 Z = 4960 - ¹¹₁₃ Y --- (2)

Make Z the same.

(1)_x8
⁸₈ Z + ⁸₁₃ Y = 4480
1 Z + ⁸₁₃ Y = 4480
1 Z = 4480 - ⁸₁₃ Y --- (3)

(3) = (2) 
4480 - ⁸₁₃ Y = 4960 - ¹¹₁₃ X
¹¹₁₃ Y - ⁸₁₃ Y = 4960 - 4480
³₁₃ Y = 480
¹₁₃ Y = 480 ÷ 3 = 160

¹³₁₃ Y = 13 x 160 = 2080

1 Y = 2080

Mass of Container Y = 2080 g

(b)
From (1)
¹₈ Z + 160 = 560
¹₈ Z = 560 - 160 = 400

⁸₈ Z = 8 x 400 = 3200

1 Z = 3200

Mass of Container Z = 3200 g

Answer(s): (a) 2080 g; (b) 3200 g