Container K and Container L were filled completely with flour. The total mass of
14 of the flour in Container L and
111 of the flour in Container K was 610 g. If
211 of the flour in Container K was poured out, the total mass of the flour in both containers became 3.39 kg. How much flour was in
- Container K in grams?
- Container L in grams?
(a)
Let the mass of the flour in Container L be L.
Let the mass of the flour in Container K be K.
14 L +
111 K = 610 --- (1)
Fraction of the flour left in Container K after
211 of it was poured out
= 1 -
211 =
911 1 kg = 1000 g
3.39 kg = 3390 g
1 L +
911 K = 3390
1 L = 3390 -
911 K --- (2)
Make L the same.
(1)
x4 44 L +
411 K = 2440
1 L +
411 K = 2440
1 L = 2440 -
411 K --- (3)
(3) = (2)
2440 -
411 K = 3390 -
911 X
911 K -
411 K = 3390 - 2440
511 K = 950
111 K = 950 ÷ 5 = 190
1111 K = 11 x 190 = 2090
1 K = 2090
Mass of Container K = 2090 g
(b)
From (1)
14 L + 190 = 610
14 L = 610 - 190 = 420
44 L = 4 x 420 = 1680
1 L = 1680
Mass of Container L = 1680 g
Answer(s): (a) 2090 g; (b) 1680 g