Container Q and Container R were filled completely with chicken powder. The total mass of ¹₆ of the chicken powder in Container R and ¹₁₁ of the chicken powder in Container Q was 500 g. If ²₁₁ of the chicken powder in Container Q was poured out, the total mass of the chicken powder in both containers became 3.42 kg. How much chicken powder was in

1. Container Q in grams?
2. Container R in grams?

(a)
Let the mass of the chicken powder in Container R be R.
Let the mass of the chicken powder in Container Q be Q.

¹₆ R + ¹₁₁ Q = 500 --- (1)

Fraction of the chicken powder left in Container Q after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
3.42 kg = 3420 g

1 R + ⁹₁₁ Q = 3420
1 R = 3420 - ⁹₁₁ Q --- (2)

Make R the same.

(1)_x6
⁶₆ R + ⁶₁₁ Q = 3000
1 R + ⁶₁₁ Q = 3000
1 R = 3000 - ⁶₁₁ Q --- (3)

(3) = (2) 
3000 - ⁶₁₁ Q = 3420 - ⁹₁₁ X
⁹₁₁ Q - ⁶₁₁ Q = 3420 - 3000
³₁₁ Q = 420
¹₁₁ Q = 420 ÷ 3 = 140

¹¹₁₁ Q = 11 x 140 = 1540

1 Q = 1540

Mass of Container Q = 1540 g

(b)
From (1)
¹₆ R + 140 = 500
¹₆ R = 500 - 140 = 360

⁶₆ R = 6 x 360 = 2160

1 R = 2160

Mass of Container R = 2160 g

Answer(s): (a) 1540 g; (b) 2160 g