Container E and Container F were filled completely with curry powder. The total mass of ¹₅ of the curry powder in Container F and ¹₁₃ of the curry powder in Container E was 440 g. If ²₁₃ of the curry powder in Container E was poured out, the total mass of the curry powder in both containers became 2.92 kg. How much curry powder was in

1. Container E in grams?
2. Container F in grams?

(a)
Let the mass of the curry powder in Container F be F.
Let the mass of the curry powder in Container E be E.

¹₅ F + ¹₁₃ E = 440 --- (1)

Fraction of the curry powder left in Container E after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
2.92 kg = 2920 g

1 F + ¹¹₁₃ E = 2920
1 F = 2920 - ¹¹₁₃ E --- (2)

Make F the same.

(1)_x5
⁵₅ F + ⁵₁₃ E = 2200
1 F + ⁵₁₃ E = 2200
1 F = 2200 - ⁵₁₃ E --- (3)

(3) = (2) 
2200 - ⁵₁₃ E = 2920 - ¹¹₁₃ X
¹¹₁₃ E - ⁵₁₃ E = 2920 - 2200
⁶₁₃ E = 720
¹₁₃ E = 720 ÷ 6 = 120

¹³₁₃ E = 13 x 120 = 1560

1 E = 1560

Mass of Container E = 1560 g

(b)
From (1)
¹₅ F + 120 = 440
¹₅ F = 440 - 120 = 320

⁵₅ F = 5 x 320 = 1600

1 F = 1600

Mass of Container F = 1600 g

Answer(s): (a) 1560 g; (b) 1600 g