Container B and Container C were filled completely with chicken powder. The total mass of
16 of the chicken powder in Container C and
113 of the chicken powder in Container B was 500 g. If
313 of the chicken powder in Container B was poured out, the total mass of the chicken powder in both containers became 3.64 kg. How much chicken powder was in
- Container B in grams?
- Container C in grams?
(a)
Let the mass of the chicken powder in Container C be C.
Let the mass of the chicken powder in Container B be B.
16 C +
113 B = 500 --- (1)
Fraction of the chicken powder left in Container B after
313 of it was poured out
= 1 -
313 =
1013 1 kg = 1000 g
3.64 kg = 3640 g
1 C +
1013 B = 3640
1 C = 3640 -
1013 B --- (2)
Make C the same.
(1)
x6 66 C +
613 B = 3000
1 C +
613 B = 3000
1 C = 3000 -
613 B --- (3)
(3) = (2)
3000 -
613 B = 3640 -
1013 X
1013 B -
613 B = 3640 - 3000
413 B = 640
113 B = 640 ÷ 4 = 160
1313 B = 13 x 160 = 2080
1 B = 2080
Mass of Container B = 2080 g
(b)
From (1)
16 C + 160 = 500
16 C = 500 - 160 = 340
66 C = 6 x 340 = 2040
1 C = 2040
Mass of Container C = 2040 g
Answer(s): (a) 2080 g; (b) 2040 g