Container F and Container G were filled completely with flour. The total mass of
15 of the flour in Container G and
111 of the flour in Container F was 480 g. If
211 of the flour in Container F was poured out, the total mass of the flour in both containers became 2.8 kg. How much flour was in
- Container F in grams?
- Container G in grams?
(a)
Let the mass of the flour in Container G be G.
Let the mass of the flour in Container F be F.
15 G +
111 F = 480 --- (1)
Fraction of the flour left in Container F after
211 of it was poured out
= 1 -
211 =
911 1 kg = 1000 g
2.8 kg = 2800 g
1 G +
911 F = 2800
1 G = 2800 -
911 F --- (2)
Make G the same.
(1)
x5 55 G +
511 F = 2400
1 G +
511 F = 2400
1 G = 2400 -
511 F --- (3)
(3) = (2)
2400 -
511 F = 2800 -
911 X
911 F -
511 F = 2800 - 2400
411 F = 400
111 F = 400 ÷ 4 = 100
1111 F = 11 x 100 = 1100
1 F = 1100
Mass of Container F = 1100 g
(b)
From (1)
15 G + 100 = 480
15 G = 480 - 100 = 380
55 G = 5 x 380 = 1900
1 G = 1900
Mass of Container G = 1900 g
Answer(s): (a) 1100 g; (b) 1900 g