Container J and Container K were filled completely with flour. The total mass of
13 of the flour in Container K and
113 of the flour in Container J was 450 g. If
313 of the flour in Container J was poured out, the total mass of the flour in both containers became 2.26 kg. How much flour was in
- Container J in grams?
- Container K in grams?
(a)
Let the mass of the flour in Container K be K.
Let the mass of the flour in Container J be J.
13 K +
113 J = 450 --- (1)
Fraction of the flour left in Container J after
313 of it was poured out
= 1 -
313 =
1013 1 kg = 1000 g
2.26 kg = 2260 g
1 K +
1013 J = 2260
1 K = 2260 -
1013 J --- (2)
Make K the same.
(1)
x3 33 K +
313 J = 1350
1 K +
313 J = 1350
1 K = 1350 -
313 J --- (3)
(3) = (2)
1350 -
313 J = 2260 -
1013 X
1013 J -
313 J = 2260 - 1350
713 J = 910
113 J = 910 ÷ 7 = 130
1313 J = 13 x 130 = 1690
1 J = 1690
Mass of Container J = 1690 g
(b)
From (1)
13 K + 130 = 450
13 K = 450 - 130 = 320
33 K = 3 x 320 = 960
1 K = 960
Mass of Container K = 960 g
Answer(s): (a) 1690 g; (b) 960 g